0.16x^2+0.08x+0.01=0.16

Solution for 0.16x^2+0.08x+0.01=0.16 equation:

0.16x^2+0.08x+0.01=0.16

We move all terms to the left:

0.16x^2+0.08x+0.01-(0.16)=0

We add all the numbers together, and all the variables

0.16x^2+0.08x-0.15=0

a = 0.16; b = 0.08; c = -0.15;
Δ = b2-4ac
Δ = 0.082-4·0.16·(-0.15)
Δ = 0.1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.08)-\sqrt{0.1024}}{2*0.16}=\frac{-0.08-\sqrt{0.1024}}{0.32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.08)+\sqrt{0.1024}}{2*0.16}=\frac{-0.08+\sqrt{0.1024}}{0.32}
$